-16x^2-320x+1584=0

Solution for -16x^2-320x+1584=0 equation:

-16x^2-320x+1584=0

a = -16; b = -320; c = +1584;
Δ = b2-4ac
Δ = -3202-4·(-16)·1584
Δ = 203776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{203776}=\sqrt{1024*199}=\sqrt{1024}*\sqrt{199}=32\sqrt{199}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-32\sqrt{199}}{2*-16}=\frac{320-32\sqrt{199}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+32\sqrt{199}}{2*-16}=\frac{320+32\sqrt{199}}{-32}
$